5/(a^2)=-4/a+1

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Solution for 5/(a^2)=-4/a+1 equation:


D( a )

a^2 = 0

a = 0

a^2 = 0

a^2 = 0

1*a^2 = 0 // : 1

a^2 = 0

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

5/(a^2) = 1-4/a // - 1-4/a

5/(a^2)-(-4/a)-1 = 0

4*a^-1+5/(a^2)-1 = 0

4*a^-1+5*a^-2-1 = 0

t_1 = a^-1

5*t_1^2+4*t_1^1-1 = 0

5*t_1^2+4*t_1-1 = 0

DELTA = 4^2-(-1*4*5)

DELTA = 36

DELTA > 0

t_1 = (36^(1/2)-4)/(2*5) or t_1 = (-36^(1/2)-4)/(2*5)

t_1 = 1/5 or t_1 = -1

t_1 = -1

a^-1+1 = 0

1*a^-1 = -1 // : 1

a^-1 = -1

-1 < 0

1/(a^1) = -1 // * a^1

1 = -1*a^1 // : -1

-1 = a^1

a = -1

t_1 = 1/5

a^-1-1/5 = 0

1*a^-1 = 1/5 // : 1

a^-1 = 1/5

-1 < 0

1/(a^1) = 1/5 // * a^1

1 = 1/5*a^1 // : 1/5

5 = a^1

a = 5

a in { -1, 5 }

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